Base | Representation |
---|---|
bin | 1001001011011001110000… |
… | …1000000101000001101111 |
3 | 1022201201220210222222000201 |
4 | 2102312130020011001233 |
5 | 2310314341332313433 |
6 | 33243545302534331 |
7 | 2061041500536622 |
oct | 222663410050157 |
9 | 38651823888021 |
10 | 10091497541743 |
11 | 3240864306412 |
12 | 116b9721373a7 |
13 | 5828162bbb77 |
14 | 26c606c8ddb9 |
15 | 1277829d0a7d |
hex | 92d9c20506f |
10091497541743 has 2 divisors, whose sum is σ = 10091497541744. Its totient is φ = 10091497541742.
The previous prime is 10091497541687. The next prime is 10091497541747. The reversal of 10091497541743 is 34714579419001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10091497541743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10091497541747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5045748770871 + 5045748770872.
It is an arithmetic number, because the mean of its divisors is an integer number (5045748770872).
Almost surely, 210091497541743 is an apocalyptic number.
10091497541743 is a deficient number, since it is larger than the sum of its proper divisors (1).
10091497541743 is an equidigital number, since it uses as much as digits as its factorization.
10091497541743 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3810240, while the sum is 55.
The spelling of 10091497541743 in words is "ten trillion, ninety-one billion, four hundred ninety-seven million, five hundred forty-one thousand, seven hundred forty-three".
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