Base | Representation |
---|---|
bin | 10110111101101111100101… |
… | …001000001111111000101111 |
3 | 111020121111122122221112211112 |
4 | 112331233211020033320233 |
5 | 101214241000012011002 |
6 | 554450432015342235 |
7 | 30163003104630326 |
oct | 2675574510177057 |
9 | 436544578845745 |
10 | 101000000110127 |
11 | 2a1aa94aaa7888 |
12 | b3b258782197b |
13 | 444834a44c941 |
14 | 1ad25d72870bd |
15 | ba2396058852 |
hex | 5bdbe520fe2f |
101000000110127 has 2 divisors, whose sum is σ = 101000000110128. Its totient is φ = 101000000110126.
The previous prime is 101000000110081. The next prime is 101000000110147. The reversal of 101000000110127 is 721011000000101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101000000110127 - 210 = 101000000109103 is a prime.
It is a super-2 number, since 2×1010000001101272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101000000110147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500000055063 + 50500000055064.
It is an arithmetic number, because the mean of its divisors is an integer number (50500000055064).
Almost surely, 2101000000110127 is an apocalyptic number.
101000000110127 is a deficient number, since it is larger than the sum of its proper divisors (1).
101000000110127 is an equidigital number, since it uses as much as digits as its factorization.
101000000110127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 101000000110127 its reverse (721011000000101), we get a palindrome (822011000110228).
The spelling of 101000000110127 in words is "one hundred one trillion, one hundred ten thousand, one hundred twenty-seven".
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