10100000113111 has 2 divisors, whose sum is σ = 10100000113112. Its totient is φ = 10100000113110.

The previous prime is 10100000113103. The next prime is 10100000113117. The reversal of 10100000113111 is 11131100000101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100000113111 - 2³ = 10100000113103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10100000113117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000056555 + 5050000056556.

It is an arithmetic number, because the mean of its divisors is an integer number (5050000056556).

Almost surely, 2^{10100000113111} is an apocalyptic number.

10100000113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100000113111 is an equidigital number, since it uses as much as digits as its factorization.

10100000113111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 10100000113111 its reverse (11131100000101), we get a palindrome (21231100113212).

The spelling of 10100000113111 in words is "ten trillion, one hundred billion, one hundred thirteen thousand, one hundred eleven".