10100011000147 has 2 divisors, whose sum is σ = 10100011000148. Its totient is φ = 10100011000146.

The previous prime is 10100011000067. The next prime is 10100011000153. The reversal of 10100011000147 is 74100011000101.

It is a happy number.

10100011000147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10100011000147 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10100011000147.

It is not a weakly prime, because it can be changed into another prime (10100011070147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050005500073 + 5050005500074.

It is an arithmetic number, because the mean of its divisors is an integer number (5050005500074).

Almost surely, 2^{10100011000147} is an apocalyptic number.

10100011000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100011000147 is an equidigital number, since it uses as much as digits as its factorization.

10100011000147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 10100011000147 its reverse (74100011000101), we get a palindrome (84200022000248).

The spelling of 10100011000147 in words is "ten trillion, one hundred billion, eleven million, one hundred forty-seven", and thus it is an aban number.