1010005050113 has 2 divisors, whose sum is σ = 1010005050114. Its totient is φ = 1010005050112.

The previous prime is 1010005050083. The next prime is 1010005050181. The reversal of 1010005050113 is 3110505000101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 532457711809 + 477547338304 = 729697^2 + 691048^2 .

It is a cyclic number.

It is not a de Polignac number, because 1010005050113 - 2¹⁸ = 1010004787969 is a prime.

It is a super-2 number, since 2×1010005050113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1010005050091 and 1010005050100.

It is not a weakly prime, because it can be changed into another prime (1010005050913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505002525056 + 505002525057.

It is an arithmetic number, because the mean of its divisors is an integer number (505002525057).

Almost surely, 2^{1010005050113} is an apocalyptic number.

It is an amenable number.

1010005050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010005050113 is an equidigital number, since it uses as much as digits as its factorization.

1010005050113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

The spelling of 1010005050113 in words is "one trillion, ten billion, five million, fifty thousand, one hundred thirteen".