10100110001083 has 2 divisors, whose sum is σ = 10100110001084. Its totient is φ = 10100110001082.

The previous prime is 10100110001057. The next prime is 10100110001099. The reversal of 10100110001083 is 38010001100101.

It is an a-pointer prime, because the next prime (10100110001099) can be obtained adding 10100110001083 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100110001083 - 2¹³ = 10100109992891 is a prime.

It is a super-2 number, since 2×10100110001083² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100110401083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050055000541 + 5050055000542.

It is an arithmetic number, because the mean of its divisors is an integer number (5050055000542).

Almost surely, 2^{10100110001083} is an apocalyptic number.

10100110001083 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100110001083 is an equidigital number, since it uses as much as digits as its factorization.

10100110001083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 10100110001083 its reverse (38010001100101), we get a palindrome (48110111101184).

The spelling of 10100110001083 in words is "ten trillion, one hundred billion, one hundred ten million, one thousand, eighty-three".