10100110001131 has 2 divisors, whose sum is σ = 10100110001132. Its totient is φ = 10100110001130.

The previous prime is 10100110001101. The next prime is 10100110001141. The reversal of 10100110001131 is 13110001100101.

It is an a-pointer prime, because the next prime (10100110001141) can be obtained adding 10100110001131 to its sum of digits (10).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100110001131 - 2⁵ = 10100110001099 is a prime.

It is a super-2 number, since 2×10100110001131² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100110001101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050055000565 + 5050055000566.

It is an arithmetic number, because the mean of its divisors is an integer number (5050055000566).

Almost surely, 2^{10100110001131} is an apocalyptic number.

10100110001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100110001131 is an equidigital number, since it uses as much as digits as its factorization.

10100110001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 10100110001131 its reverse (13110001100101), we get a palindrome (23210111101232).

The spelling of 10100110001131 in words is "ten trillion, one hundred billion, one hundred ten million, one thousand, one hundred thirty-one".