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101001111112093 is a prime number
BaseRepresentation
bin10110111101110000100111…
…010110011000100110011101
3111020121121112002111022000111
4112331300213112120212131
5101214300233421041333
6554451134144130021
730163042455165163
oct2675604726304635
9436547462438014
10101001111112093
112a200370147025
12b3b2837906911
13444849668325a
141ad26a0a4b233
15ba240d8644cd
hex5bdc2759899d

101001111112093 has 2 divisors, whose sum is σ = 101001111112094. Its totient is φ = 101001111112092.

The previous prime is 101001111112079. The next prime is 101001111112123. The reversal of 101001111112093 is 390211111100101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96809010470649 + 4192100641444 = 9839157^2 + 2047462^2 .

It is an emirp because it is prime and its reverse (390211111100101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101001111112093 - 245 = 65816739023261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101001111112003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500555556046 + 50500555556047.

It is an arithmetic number, because the mean of its divisors is an integer number (50500555556047).

Almost surely, 2101001111112093 is an apocalyptic number.

It is an amenable number.

101001111112093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101001111112093 is an equidigital number, since it uses as much as digits as its factorization.

101001111112093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 22.

Adding to 101001111112093 its reverse (390211111100101), we get a palindrome (491212222212194).

The spelling of 101001111112093 in words is "one hundred one trillion, one billion, one hundred eleven million, one hundred twelve thousand, ninety-three".