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101001121112233 is a prime number
BaseRepresentation
bin10110111101110000100111…
…111100100010000010101001
3111020121121112210022100122001
4112331300213330202002221
5101214300244001042413
6554451135142331001
730163042636165126
oct2675604774420251
9436547483270561
10101001121112233
112a200375857301
12b3b283b129a61
134448498774bb4
141ad26a20d174d
15ba240e68c4dd
hex5bdc27f220a9

101001121112233 has 2 divisors, whose sum is σ = 101001121112234. Its totient is φ = 101001121112232.

The previous prime is 101001121112189. The next prime is 101001121112237. The reversal of 101001121112233 is 332211121100101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95901125439744 + 5099995672489 = 9792912^2 + 2258317^2 .

It is a cyclic number.

It is not a de Polignac number, because 101001121112233 - 213 = 101001121104041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101001121112233.

It is not a weakly prime, because it can be changed into another prime (101001121112237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500560556116 + 50500560556117.

It is an arithmetic number, because the mean of its divisors is an integer number (50500560556117).

Almost surely, 2101001121112233 is an apocalyptic number.

It is an amenable number.

101001121112233 is a deficient number, since it is larger than the sum of its proper divisors (1).

101001121112233 is an equidigital number, since it uses as much as digits as its factorization.

101001121112233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 101001121112233 its reverse (332211121100101), we get a palindrome (433212242212334).

The spelling of 101001121112233 in words is "one hundred one trillion, one billion, one hundred twenty-one million, one hundred twelve thousand, two hundred thirty-three".