10100113003121 has 4 divisors (see below), whose sum is σ = 10315009024512. Its totient is φ = 9885216981732.

The previous prime is 10100113003091. The next prime is 10100113003129. The reversal of 10100113003121 is 12130031100101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10100113003121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10100113003096 and 10100113003105.

It is not an unprimeable number, because it can be changed into a prime (10100113003129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107448010625 + ... + 107448010718.

It is an arithmetic number, because the mean of its divisors is an integer number (2578752256128).

Almost surely, 2^{10100113003121} is an apocalyptic number.

It is an amenable number.

10100113003121 is a deficient number, since it is larger than the sum of its proper divisors (214896021391).

10100113003121 is an equidigital number, since it uses as much as digits as its factorization.

10100113003121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 214896021390.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10100113003121 its reverse (12130031100101), we get a palindrome (22230144103222).

The spelling of 10100113003121 in words is "ten trillion, one hundred billion, one hundred thirteen million, three thousand, one hundred twenty-one".