Base | Representation |
---|---|
bin | 10010110100000001… |
… | …10111111101000111 |
3 | 222001220010220122112 |
4 | 21122000313331013 |
5 | 131141112110343 |
6 | 4350120251235 |
7 | 505201355144 |
oct | 113200677507 |
9 | 28056126575 |
10 | 10100113223 |
11 | 4313283612 |
12 | 1b5a610b1b |
13 | c4c670675 |
14 | 6bb5833cb |
15 | 3e1a86218 |
hex | 25a037f47 |
10100113223 has 2 divisors, whose sum is σ = 10100113224. Its totient is φ = 10100113222.
The previous prime is 10100113189. The next prime is 10100113241. The reversal of 10100113223 is 32231100101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10100113223 - 216 = 10100047687 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10100113198 and 10100113207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10100113273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050056611 + 5050056612.
It is an arithmetic number, because the mean of its divisors is an integer number (5050056612).
Almost surely, 210100113223 is an apocalyptic number.
10100113223 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100113223 is an equidigital number, since it uses as much as digits as its factorization.
10100113223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 10100113223 its reverse (32231100101), we get a palindrome (42331213324).
The spelling of 10100113223 in words is "ten billion, one hundred million, one hundred thirteen thousand, two hundred twenty-three".
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