Base | Representation |
---|---|
bin | 11101011001010010110… |
… | …10001011011100000011 |
3 | 10120120000110211220111212 |
4 | 32230221122023130003 |
5 | 113022001040334021 |
6 | 2051554303200335 |
7 | 132654016466546 |
oct | 16545132133403 |
9 | 3516013756455 |
10 | 1010012043011 |
11 | 35a386516004 |
12 | 1438b6ba60ab |
13 | 7432261174a |
14 | 36c5602285d |
15 | 1b41570285b |
hex | eb2968b703 |
1010012043011 has 2 divisors, whose sum is σ = 1010012043012. Its totient is φ = 1010012043010.
The previous prime is 1010012042959. The next prime is 1010012043013. The reversal of 1010012043011 is 1103402100101.
1010012043011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1010012043011 - 218 = 1010011780867 is a prime.
It is a super-2 number, since 2×10100120430112 (a number of 25 digits) contains 22 as substring.
Together with 1010012043013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1010012043013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505006021505 + 505006021506.
It is an arithmetic number, because the mean of its divisors is an integer number (505006021506).
Almost surely, 21010012043011 is an apocalyptic number.
1010012043011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010012043011 is an equidigital number, since it uses as much as digits as its factorization.
1010012043011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1010012043011 its reverse (1103402100101), we get a palindrome (2113414143112).
The spelling of 1010012043011 in words is "one trillion, ten billion, twelve million, forty-three thousand, eleven".
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