10100132113 has 4 divisors (see below), whose sum is σ = 10142392320. Its totient is φ = 10057871908.

The previous prime is 10100132087. The next prime is 10100132171. The reversal of 10100132113 is 31123100101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10100132113 - 2¹³ = 10100123921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10100132093 and 10100132102.

It is not an unprimeable number, because it can be changed into a prime (10100132173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21129745 + ... + 21130222.

It is an arithmetic number, because the mean of its divisors is an integer number (2535598080).

Almost surely, 2^10100132113 is an apocalyptic number.

It is an amenable number.

10100132113 is a deficient number, since it is larger than the sum of its proper divisors (42260207).

10100132113 is an equidigital number, since it uses as much as digits as its factorization.

10100132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42260206.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10100132113 its reverse (31123100101), we get a palindrome (41223232214).

The spelling of 10100132113 in words is "ten billion, one hundred million, one hundred thirty-two thousand, one hundred thirteen".