Base | Representation |
---|---|
bin | 1001001011111001111011… |
… | …0101110100000111100011 |
3 | 1022202120012122011201101121 |
4 | 2102332132311310013203 |
5 | 2310440033023121011 |
6 | 33251534223113111 |
7 | 2061465466102510 |
oct | 222763665640743 |
9 | 38676178151347 |
10 | 10100133020131 |
11 | 3244495864110 |
12 | 1171582142797 |
13 | 5835913a02ab |
14 | 26cbc5ad8307 |
15 | 127adaba5e71 |
hex | 92f9ed741e3 |
10100133020131 has 32 divisors (see below), whose sum is σ = 12766535815680. Its totient is φ = 7761988608000.
The previous prime is 10100133020083. The next prime is 10100133020147. The reversal of 10100133020131 is 13102033100101.
It is not a de Polignac number, because 10100133020131 - 213 = 10100133011939 is a prime.
It is a super-2 number, since 2×101001330201312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10100133020191) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 528001 + ... + 4525378.
It is an arithmetic number, because the mean of its divisors is an integer number (398954244240).
Almost surely, 210100133020131 is an apocalyptic number.
10100133020131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
10100133020131 is a deficient number, since it is larger than the sum of its proper divisors (2666402795549).
10100133020131 is a wasteful number, since it uses less digits than its factorization.
10100133020131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5053755.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 10100133020131 its reverse (13102033100101), we get a palindrome (23202166120232).
The spelling of 10100133020131 in words is "ten trillion, one hundred billion, one hundred thirty-three million, twenty thousand, one hundred thirty-one".
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