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10100201311 is a prime number
BaseRepresentation
bin10010110100000010…
…01101011101011111
3222001220022101111001
421122001031131133
5131141122420221
64350122211131
7505202203024
oct113201153537
928056271431
1010100201311
114313333812
121b5a653aa7
13c4c6a17a5
146bb5a754b
153e1aa2391
hex25a04d75f

10100201311 has 2 divisors, whose sum is σ = 10100201312. Its totient is φ = 10100201310.

The previous prime is 10100201227. The next prime is 10100201323. The reversal of 10100201311 is 11310200101.

10100201311 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11310200101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10100201311 - 27 = 10100201183 is a prime.

It is a super-2 number, since 2×101002013112 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10100201351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050100655 + 5050100656.

It is an arithmetic number, because the mean of its divisors is an integer number (5050100656).

Almost surely, 210100201311 is an apocalyptic number.

10100201311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100201311 is an equidigital number, since it uses as much as digits as its factorization.

10100201311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 10100201311 its reverse (11310200101), we get a palindrome (21410401412).

The spelling of 10100201311 in words is "ten billion, one hundred million, two hundred one thousand, three hundred eleven".