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10100210312314 = 25050105156157
BaseRepresentation
bin1001001011111010001101…
…1100101010010001111010
31022202120102000121120100001
42102332203130222101322
52310440212314443224
633251550023503214
72061500425060243
oct222764334522172
938676360546301
1010100210312314
113244525455951
1211715a3bb7b0a
135835a43c3005
1426cbd2097cca
15127ae2872544
hex92fa372a47a

10100210312314 has 4 divisors (see below), whose sum is σ = 15150315468474. Its totient is φ = 5050105156156.

The previous prime is 10100210312267. The next prime is 10100210312327. The reversal of 10100210312314 is 41321301200101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10091950229089 + 8260083225 = 3176783^2 + 90885^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10100210312291 and 10100210312300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525052578077 + ... + 2525052578080.

Almost surely, 210100210312314 is an apocalyptic number.

10100210312314 is a deficient number, since it is larger than the sum of its proper divisors (5050105156160).

10100210312314 is an equidigital number, since it uses as much as digits as its factorization.

10100210312314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5050105156159.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10100210312314 its reverse (41321301200101), we get a palindrome (51421511512415).

The spelling of 10100210312314 in words is "ten trillion, one hundred billion, two hundred ten million, three hundred twelve thousand, three hundred fourteen".

Divisors: 1 2 5050105156157 10100210312314