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10100283424807 is a prime number
BaseRepresentation
bin1001001011111010011111…
…0011100100000000100111
31022202120121010012001211011
42102332213303210000213
52310440340024043212
633252001154523051
72061502303366222
oct222764763440047
938676533161734
1010100283424807
1132445627523a4
121171604596487
135835b65b1444
1426cbdba8a5b9
15127ae8eb54a7
hex92fa7ce4027

10100283424807 has 2 divisors, whose sum is σ = 10100283424808. Its totient is φ = 10100283424806.

The previous prime is 10100283424793. The next prime is 10100283424813. The reversal of 10100283424807 is 70842438200101.

10100283424807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100283424807 - 223 = 10100275036199 is a prime.

It is a super-2 number, since 2×101002834248072 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10100283424807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10100283424817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050141712403 + 5050141712404.

It is an arithmetic number, because the mean of its divisors is an integer number (5050141712404).

Almost surely, 210100283424807 is an apocalyptic number.

10100283424807 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100283424807 is an equidigital number, since it uses as much as digits as its factorization.

10100283424807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86016, while the sum is 40.

The spelling of 10100283424807 in words is "ten trillion, one hundred billion, two hundred eighty-three million, four hundred twenty-four thousand, eight hundred seven".