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101003113 = 1371634523
BaseRepresentation
bin1100000010100…
…10111101101001
321001001111020001
412001102331221
5201324044423
614004503001
72334340501
oct601227551
9231044201
10101003113
1152017152
12299aaa61
1317c05273
14d5b2a01
158d01cad
hex6052f69

101003113 has 8 divisors (see below), whose sum is σ = 102387168. Its totient is φ = 99628704.

The previous prime is 101003101. The next prime is 101003179. The reversal of 101003113 is 311300101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101003113 - 213 = 100994921 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101003113.

It is not an unprimeable number, because it can be changed into a prime (101003713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20070 + ... + 24592.

It is an arithmetic number, because the mean of its divisors is an integer number (12798396).

Almost surely, 2101003113 is an apocalyptic number.

It is an amenable number.

101003113 is a deficient number, since it is larger than the sum of its proper divisors (1384055).

101003113 is a wasteful number, since it uses less digits than its factorization.

101003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4823.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 101003113 is about 10050.0304974662. The cubic root of 101003113 is about 465.7057353090.

Adding to 101003113 its reverse (311300101), we get a palindrome (412303214).

The spelling of 101003113 in words is "one hundred one million, three thousand, one hundred thirteen".

Divisors: 1 137 163 4523 22331 619651 737249 101003113