Base | Representation |
---|---|
bin | 1001001011111011011100… |
… | …0111011111000000000011 |
3 | 1022202121021000112221202121 |
4 | 2102332313013133000003 |
5 | 2310441401304233121 |
6 | 33252042452425111 |
7 | 2061511543006243 |
oct | 222766707370003 |
9 | 38677230487677 |
10 | 10100540305411 |
11 | 3244684755616 |
12 | 1171676618197 |
13 | 5836278928ba |
14 | 26cc23c37b23 |
15 | 127b11808141 |
hex | 92fb71df003 |
10100540305411 has 2 divisors, whose sum is σ = 10100540305412. Its totient is φ = 10100540305410.
The previous prime is 10100540305321. The next prime is 10100540305441. The reversal of 10100540305411 is 11450304500101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10100540305411 - 215 = 10100540272643 is a prime.
It is a super-2 number, since 2×101005403054112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10100540305441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050270152705 + 5050270152706.
It is an arithmetic number, because the mean of its divisors is an integer number (5050270152706).
Almost surely, 210100540305411 is an apocalyptic number.
10100540305411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100540305411 is an equidigital number, since it uses as much as digits as its factorization.
10100540305411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 10100540305411 its reverse (11450304500101), we get a palindrome (21550844805512).
The spelling of 10100540305411 in words is "ten trillion, one hundred billion, five hundred forty million, three hundred five thousand, four hundred eleven".
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