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10101000113 = 69111461583
BaseRepresentation
bin10010110100001000…
…10000011110110001
3222001221210222020022
421122010100132301
5131141324000423
64350151253225
7505212040631
oct113204203661
928057728208
1010101000113
114313829986
121b5a97a215
13c4c8c1259
146bb7346c1
153e1baddc8
hex25a1107b1

10101000113 has 4 divisors (see below), whose sum is σ = 10102468608. Its totient is φ = 10099531620.

The previous prime is 10101000059. The next prime is 10101000127. The reversal of 10101000113 is 31100010101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10101000113 - 214 = 10100983729 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10101000113.

It is not an unprimeable number, because it can be changed into a prime (10101002113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723881 + ... + 737702.

It is an arithmetic number, because the mean of its divisors is an integer number (2525617152).

Almost surely, 210101000113 is an apocalyptic number.

It is an amenable number.

10101000113 is a deficient number, since it is larger than the sum of its proper divisors (1468495).

10101000113 is an equidigital number, since it uses as much as digits as its factorization.

10101000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1468494.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 10101000113 its reverse (31100010101), we get a palindrome (41201010214).

The spelling of 10101000113 in words is "ten billion, one hundred one million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 6911 1461583 10101000113