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101010700000081 is a prime number
BaseRepresentation
bin10110111101111001100010…
…111001000101101101010001
3111020122112021100200021111001
4112331321202321011231101
5101214424403200000311
6554455401443222001
730163532211324634
oct2675714271055521
9436575240607431
10101010700000081
112a204440896543
12b3b4673077901
13444936413b381
141ad2d30355c1b
15ba27c05b64c1
hex5bde62e45b51

101010700000081 has 2 divisors, whose sum is σ = 101010700000082. Its totient is φ = 101010700000080.

The previous prime is 101010700000079. The next prime is 101010700000097. The reversal of 101010700000081 is 180000007010101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97673194850625 + 3337505149456 = 9882975^2 + 1826884^2 .

It is a cyclic number.

It is not a de Polignac number, because 101010700000081 - 21 = 101010700000079 is a prime.

It is a super-2 number, since 2×1010107000000812 (a number of 29 digits) contains 22 as substring.

Together with 101010700000079, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (101010700000031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505350000040 + 50505350000041.

It is an arithmetic number, because the mean of its divisors is an integer number (50505350000041).

Almost surely, 2101010700000081 is an apocalyptic number.

It is an amenable number.

101010700000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

101010700000081 is an equidigital number, since it uses as much as digits as its factorization.

101010700000081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 101010700000081 its reverse (180000007010101), we get a palindrome (281010707010182).

The spelling of 101010700000081 in words is "one hundred one trillion, ten billion, seven hundred million, eighty-one", and thus it is an aban number.