Base | Representation |
---|---|
bin | 11101011001011110011… |
… | …11110110101110101011 |
3 | 10120120021022011122022002 |
4 | 32230233033312232223 |
5 | 113022201130000133 |
6 | 2052012122521215 |
7 | 132656316222554 |
oct | 16545717665653 |
9 | 3516238148262 |
10 | 1010110000043 |
11 | 35a426841631 |
12 | 14392396620b |
13 | 743399bb3a1 |
14 | 36c6504132b |
15 | 1b41e101ce8 |
hex | eb2f3f6bab |
1010110000043 has 2 divisors, whose sum is σ = 1010110000044. Its totient is φ = 1010110000042.
The previous prime is 1010110000007. The next prime is 1010110000057. The reversal of 1010110000043 is 3400000110101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1010110000043 - 216 = 1010109934507 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1010109999979 and 1010110000033.
It is not a weakly prime, because it can be changed into another prime (1010110000073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505055000021 + 505055000022.
It is an arithmetic number, because the mean of its divisors is an integer number (505055000022).
Almost surely, 21010110000043 is an apocalyptic number.
1010110000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010110000043 is an equidigital number, since it uses as much as digits as its factorization.
1010110000043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 1010110000043 its reverse (3400000110101), we get a palindrome (4410110110144).
The spelling of 1010110000043 in words is "one trillion, ten billion, one hundred ten million, forty-three", and thus it is an aban number.
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