1010111322021 has 4 divisors (see below), whose sum is σ = 1346815096032. Its totient is φ = 673407548012.

The previous prime is 1010111322019. The next prime is 1010111322043. The reversal of 1010111322021 is 1202231110101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1010111322021 - 2¹ = 1010111322019 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1010111322721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168351887001 + ... + 168351887006.

It is an arithmetic number, because the mean of its divisors is an integer number (336703774008).

Almost surely, 2^{1010111322021} is an apocalyptic number.

It is an amenable number.

1010111322021 is a deficient number, since it is larger than the sum of its proper divisors (336703774011).

1010111322021 is an equidigital number, since it uses as much as digits as its factorization.

1010111322021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 336703774010.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1010111322021 its reverse (1202231110101), we get a palindrome (2212342432122).

The spelling of 1010111322021 in words is "one trillion, ten billion, one hundred eleven million, three hundred twenty-two thousand, twenty-one".