Base | Representation |
---|---|
bin | 101111000010010111… |
… | …0111001001011000011 |
3 | 100122201122021020010122 |
4 | 1132010232321023003 |
5 | 3123332322224443 |
6 | 114223123050455 |
7 | 10204102315325 |
oct | 1360456711303 |
9 | 318648236118 |
10 | 101011133123 |
11 | 3992517340a |
12 | 176b0510a2b |
13 | 96aa147174 |
14 | 4c63469615 |
15 | 2962db9968 |
hex | 1784bb92c3 |
101011133123 has 2 divisors, whose sum is σ = 101011133124. Its totient is φ = 101011133122.
The previous prime is 101011133101. The next prime is 101011133173. The reversal of 101011133123 is 321331110101.
It is a weak prime.
It is an emirp because it is prime and its reverse (321331110101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101011133123 - 26 = 101011133059 is a prime.
It is not a weakly prime, because it can be changed into another prime (101011133173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505566561 + 50505566562.
It is an arithmetic number, because the mean of its divisors is an integer number (50505566562).
Almost surely, 2101011133123 is an apocalyptic number.
101011133123 is a deficient number, since it is larger than the sum of its proper divisors (1).
101011133123 is an equidigital number, since it uses as much as digits as its factorization.
101011133123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 101011133123 its reverse (321331110101), we get a palindrome (422342243224).
The spelling of 101011133123 in words is "one hundred one billion, eleven million, one hundred thirty-three thousand, one hundred twenty-three".
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