10101155031113 has 2 divisors, whose sum is σ = 10101155031114. Its totient is φ = 10101155031112.

The previous prime is 10101155031061. The next prime is 10101155031151. The reversal of 10101155031113 is 31113055110101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9738375285769 + 362779745344 = 3120637^2 + 602312^2 .

It is a cyclic number.

It is not a de Polignac number, because 10101155031113 - 2¹⁰ = 10101155030089 is a prime.

It is not a weakly prime, because it can be changed into another prime (10101155031713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050577515556 + 5050577515557.

It is an arithmetic number, because the mean of its divisors is an integer number (5050577515557).

Almost surely, 2^{10101155031113} is an apocalyptic number.

It is an amenable number.

10101155031113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10101155031113 is an equidigital number, since it uses as much as digits as its factorization.

10101155031113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 23.

The spelling of 10101155031113 in words is "ten trillion, one hundred one billion, one hundred fifty-five million, thirty-one thousand, one hundred thirteen".