101020000112313 has 4 divisors (see below), whose sum is σ = 134693333483088. Its totient is φ = 67346666741540.

The previous prime is 101020000112303. The next prime is 101020000112347. The reversal of 101020000112313 is 313211000020101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101020000112313 - 2²¹ = 101019998015161 is a prime.

It is a super-3 number, since 3×101020000112313³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 101020000112292 and 101020000112301.

It is not an unprimeable number, because it can be changed into a prime (101020000112303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16836666685383 + ... + 16836666685388.

It is an arithmetic number, because the mean of its divisors is an integer number (33673333370772).

Almost surely, 2^{101020000112313} is an apocalyptic number.

It is an amenable number.

101020000112313 is a deficient number, since it is larger than the sum of its proper divisors (33673333370775).

101020000112313 is an equidigital number, since it uses as much as digits as its factorization.

101020000112313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33673333370774.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 101020000112313 its reverse (313211000020101), we get a palindrome (414231000132414).

The spelling of 101020000112313 in words is "one hundred one trillion, twenty billion, one hundred twelve thousand, three hundred thirteen".