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101021211020131 is a prime number
BaseRepresentation
bin10110111110000011010101…
…011001011100101101100011
3111020200112101220000102022221
4112332003111121130231203
5101220112420010121011
6554504300443011511
730164353532452153
oct2676032531345543
9436615356012287
10101021211020131
112a208945004476
12b3b6707209b97
13444a34a96b86c
141ad364a2dc763
15ba2bd8267971
hex5be0d565cb63

101021211020131 has 2 divisors, whose sum is σ = 101021211020132. Its totient is φ = 101021211020130.

The previous prime is 101021211020087. The next prime is 101021211020159. The reversal of 101021211020131 is 131020112120101.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (131020112120101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101021211020131 - 217 = 101021210889059 is a prime.

It is a super-2 number, since 2×1010212110201312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101021211024131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50510605510065 + 50510605510066.

It is an arithmetic number, because the mean of its divisors is an integer number (50510605510066).

Almost surely, 2101021211020131 is an apocalyptic number.

101021211020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101021211020131 is an equidigital number, since it uses as much as digits as its factorization.

101021211020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 101021211020131 its reverse (131020112120101), we get a palindrome (232041323140232).

The spelling of 101021211020131 in words is "one hundred one trillion, twenty-one billion, two hundred eleven million, twenty thousand, one hundred thirty-one".