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10102123113 = 33367374371
BaseRepresentation
bin10010110100010001…
…00010101001101001
3222002000221000200220
421122020202221221
5131142120414423
64350231320253
7505224425655
oct113210425151
928060830626
1010102123113
114314426685
121b5b220089
13c4cbc5454
146bb947a65
153e1d319e3
hex25a222a69

10102123113 has 4 divisors (see below), whose sum is σ = 13469497488. Its totient is φ = 6734748740.

The previous prime is 10102123111. The next prime is 10102123159. The reversal of 10102123113 is 31132120101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10102123113 - 21 = 10102123111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10102123092 and 10102123101.

It is not an unprimeable number, because it can be changed into a prime (10102123111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683687183 + ... + 1683687188.

It is an arithmetic number, because the mean of its divisors is an integer number (3367374372).

Almost surely, 210102123113 is an apocalyptic number.

It is an amenable number.

10102123113 is a deficient number, since it is larger than the sum of its proper divisors (3367374375).

10102123113 is an equidigital number, since it uses as much as digits as its factorization.

10102123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3367374374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10102123113 its reverse (31132120101), we get a palindrome (41234243214).

The spelling of 10102123113 in words is "ten billion, one hundred two million, one hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 3 3367374371 10102123113