1010402113 has 4 divisors (see below), whose sum is σ = 1154745280. Its totient is φ = 866058948.

The previous prime is 1010402111. The next prime is 1010402117. The reversal of 1010402113 is 3112040101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112040101 = 44381 ⋅70121.

It is a cyclic number.

It is not a de Polignac number, because 1010402113 - 2¹ = 1010402111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1010402093 and 1010402102.

It is not an unprimeable number, because it can be changed into a prime (1010402111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72171573 + ... + 72171586.

It is an arithmetic number, because the mean of its divisors is an integer number (288686320).

Almost surely, 2^1010402113 is an apocalyptic number.

It is an amenable number.

1010402113 is a deficient number, since it is larger than the sum of its proper divisors (144343167).

1010402113 is an equidigital number, since it uses as much as digits as its factorization.

1010402113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 144343166.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1010402113 is about 31786.8229459945. The cubic root of 1010402113 is about 1003.4554173386.

Adding to 1010402113 its reverse (3112040101), we get a palindrome (4122442214).

The spelling of 1010402113 in words is "one billion, ten million, four hundred two thousand, one hundred thirteen".