Base | Representation |
---|---|
bin | 10010110100100010… |
… | …10011011011001011 |
3 | 222002012020201111101 |
4 | 21122101103123023 |
5 | 131143212420133 |
6 | 4350352442231 |
7 | 505253103364 |
oct | 113221233313 |
9 | 28065221441 |
10 | 10104420043 |
11 | 4315755373 |
12 | 1b5bb49377 |
13 | c5051aa93 |
14 | 6bbd84b6b |
15 | 3e213737d |
hex | 25a4536cb |
10104420043 has 2 divisors, whose sum is σ = 10104420044. Its totient is φ = 10104420042.
The previous prime is 10104420031. The next prime is 10104420061. The reversal of 10104420043 is 34002440101.
10104420043 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10104420043 - 29 = 10104419531 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10104420043.
It is not a weakly prime, because it can be changed into another prime (10104420143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5052210021 + 5052210022.
It is an arithmetic number, because the mean of its divisors is an integer number (5052210022).
Almost surely, 210104420043 is an apocalyptic number.
10104420043 is a deficient number, since it is larger than the sum of its proper divisors (1).
10104420043 is an equidigital number, since it uses as much as digits as its factorization.
10104420043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 10104420043 its reverse (34002440101), we get a palindrome (44106860144).
The spelling of 10104420043 in words is "ten billion, one hundred four million, four hundred twenty thousand, forty-three".
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