Base | Representation |
---|---|
bin | 101111000011100010… |
… | …1001001001001010011 |
3 | 100122211101101021222022 |
4 | 1132013011021021103 |
5 | 3123422413121042 |
6 | 114231051202055 |
7 | 10205061151313 |
oct | 1360705111123 |
9 | 318741337868 |
10 | 101050520147 |
11 | 39945425475 |
12 | 1770174632b |
13 | 96b53579b5 |
14 | 4c6879d443 |
15 | 2966599cd2 |
hex | 1787149253 |
101050520147 has 2 divisors, whose sum is σ = 101050520148. Its totient is φ = 101050520146.
The previous prime is 101050520119. The next prime is 101050520159. The reversal of 101050520147 is 741025050101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101050520147 - 226 = 100983411283 is a prime.
It is a super-2 number, since 2×1010505201472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101050520117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50525260073 + 50525260074.
It is an arithmetic number, because the mean of its divisors is an integer number (50525260074).
Almost surely, 2101050520147 is an apocalyptic number.
101050520147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101050520147 is an equidigital number, since it uses as much as digits as its factorization.
101050520147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1400, while the sum is 26.
Adding to 101050520147 its reverse (741025050101), we get a palindrome (842075570248).
The spelling of 101050520147 in words is "one hundred one billion, fifty million, five hundred twenty thousand, one hundred forty-seven".
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