10109049253951 has 2 divisors, whose sum is σ = 10109049253952. Its totient is φ = 10109049253950.

The previous prime is 10109049253939. The next prime is 10109049253973. The reversal of 10109049253951 is 15935294090101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10109049253951 is a prime.

It is a super-3 number, since 3×10109049253951³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10109049253895 and 10109049253904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10109049223951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5054524626975 + 5054524626976.

It is an arithmetic number, because the mean of its divisors is an integer number (5054524626976).

Almost surely, 2^{10109049253951} is an apocalyptic number.

10109049253951 is a deficient number, since it is larger than the sum of its proper divisors (1).

10109049253951 is an equidigital number, since it uses as much as digits as its factorization.

10109049253951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 437400, while the sum is 49.

The spelling of 10109049253951 in words is "ten trillion, one hundred nine billion, forty-nine million, two hundred fifty-three thousand, nine hundred fifty-one".