10110001000613 has 2 divisors, whose sum is σ = 10110001000614. Its totient is φ = 10110001000612.

The previous prime is 10110001000609. The next prime is 10110001000651. The reversal of 10110001000613 is 31600010001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5917654660129 + 4192346340484 = 2432623^2 + 2047522^2 .

It is an emirp because it is prime and its reverse (31600010001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10110001000613 - 2² = 10110001000609 is a prime.

It is a super-2 number, since 2×10110001000613² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110001000013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055000500306 + 5055000500307.

It is an arithmetic number, because the mean of its divisors is an integer number (5055000500307).

Almost surely, 2^{10110001000613} is an apocalyptic number.

It is an amenable number.

10110001000613 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110001000613 is an equidigital number, since it uses as much as digits as its factorization.

10110001000613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10110001000613 its reverse (31600010001101), we get a palindrome (41710011001714).

The spelling of 10110001000613 in words is "ten trillion, one hundred ten billion, one million, six hundred thirteen", and thus it is an aban number.