10110010110113 has 2 divisors, whose sum is σ = 10110010110114. Its totient is φ = 10110010110112.

The previous prime is 10110010110049. The next prime is 10110010110119. The reversal of 10110010110113 is 31101101001101.

10110010110113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9794596455424 + 315413654689 = 3129632^2 + 561617^2 .

It is an emirp because it is prime and its reverse (31101101001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10110010110113 - 2⁶ = 10110010110049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110010110094 and 10110010110103.

It is not a weakly prime, because it can be changed into another prime (10110010110119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005055056 + 5055005055057.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005055057).

Almost surely, 2^{10110010110113} is an apocalyptic number.

It is an amenable number.

10110010110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110010110113 is an equidigital number, since it uses as much as digits as its factorization.

10110010110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 10110010110113 its reverse (31101101001101), we get a palindrome (41211111111214).

The spelling of 10110010110113 in words is "ten trillion, one hundred ten billion, ten million, one hundred ten thousand, one hundred thirteen".