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101100201587813 is a prime number
BaseRepresentation
bin10110111111001100111001…
…100110100011010001100101
3111020222002021212201000111202
4112333030321212203101211
5101222411203101302223
6555004442541012245
730203151146266331
oct2677147146432145
9436862255630452
10101100201587813
112a23939a13506a
12b409a90b54085
13445492891313c
141ad73c0d927c1
15ba4cacce0428
hex5bf3399a3465

101100201587813 has 2 divisors, whose sum is σ = 101100201587814. Its totient is φ = 101100201587812.

The previous prime is 101100201587807. The next prime is 101100201587821. The reversal of 101100201587813 is 318785102001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58862069754244 + 42238131833569 = 7672162^2 + 6499087^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100201587813 - 210 = 101100201586789 is a prime.

It is a super-2 number, since 2×1011002015878132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100201580813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550100793906 + 50550100793907.

It is an arithmetic number, because the mean of its divisors is an integer number (50550100793907).

Almost surely, 2101100201587813 is an apocalyptic number.

It is an amenable number.

101100201587813 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100201587813 is an equidigital number, since it uses as much as digits as its factorization.

101100201587813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 38.

Adding to 101100201587813 its reverse (318785102001101), we get a palindrome (419885303588914).

The spelling of 101100201587813 in words is "one hundred one trillion, one hundred billion, two hundred one million, five hundred eighty-seven thousand, eight hundred thirteen".