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10110055505051 = 35328640383867
BaseRepresentation
bin1001001100011110111001…
…0001000101110010011011
31022210111211011002011211002
42103013232101011302123
52311120343202130201
633300255000255215
72062266412611125
oct223075621056233
938714734064732
1010110055505051
113248717844977
12117349117150b
135844b2cba448
1426d487840215
15127ebbd5176b
hex931ee445c9b

10110055505051 has 4 divisors (see below), whose sum is σ = 10138695889272. Its totient is φ = 10081415120832.

The previous prime is 10110055505021. The next prime is 10110055505059. The reversal of 10110055505051 is 15050555001101.

It is a happy number.

10110055505051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10110055505051 - 210 = 10110055504027 is a prime.

It is a super-3 number, since 3×101100555050513 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10110055505059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14320191581 + ... + 14320192286.

It is an arithmetic number, because the mean of its divisors is an integer number (2534673972318).

Almost surely, 210110055505051 is an apocalyptic number.

10110055505051 is a deficient number, since it is larger than the sum of its proper divisors (28640384221).

10110055505051 is an equidigital number, since it uses as much as digits as its factorization.

10110055505051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28640384220.

The product of its (nonzero) digits is 3125, while the sum is 29.

The spelling of 10110055505051 in words is "ten trillion, one hundred ten billion, fifty-five million, five hundred five thousand, fifty-one".

Divisors: 1 353 28640383867 10110055505051