Base | Representation |
---|---|
bin | 1001001100011111000011… |
… | …0110101011011010111111 |
3 | 1022210111221011202112021101 |
4 | 2103013300312223122333 |
5 | 2311120440310203314 |
6 | 33300303150513531 |
7 | 2062300450561603 |
oct | 223076066533277 |
9 | 38714834675241 |
10 | 10110098912959 |
11 | 324873a2a2981 |
12 | 11734a38058a7 |
13 | 5844bbca81b6 |
14 | 26d48d4dd503 |
15 | 127ec0a78174 |
hex | 931f0dab6bf |
10110098912959 has 2 divisors, whose sum is σ = 10110098912960. Its totient is φ = 10110098912958.
The previous prime is 10110098912933. The next prime is 10110098912993. The reversal of 10110098912959 is 95921989001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10110098912959 - 239 = 9560343099071 is a prime.
It is a super-5 number, since 5×101100989129595 (a number of 66 digits) contains 55555 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110098912999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055049456479 + 5055049456480.
It is an arithmetic number, because the mean of its divisors is an integer number (5055049456480).
Almost surely, 210110098912959 is an apocalyptic number.
10110098912959 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110098912959 is an equidigital number, since it uses as much as digits as its factorization.
10110098912959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 55.
The spelling of 10110098912959 in words is "ten trillion, one hundred ten billion, ninety-eight million, nine hundred twelve thousand, nine hundred fifty-nine".
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