1011009999863 has 2 divisors, whose sum is σ = 1011009999864. Its totient is φ = 1011009999862.

The previous prime is 1011009999847. The next prime is 1011009999889. The reversal of 1011009999863 is 3689999001101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011009999863 - 2⁴ = 1011009999847 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011009999799 and 1011009999808.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011009909863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505504999931 + 505504999932.

It is an arithmetic number, because the mean of its divisors is an integer number (505504999932).

Almost surely, 2^{1011009999863} is an apocalyptic number.

1011009999863 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011009999863 is an equidigital number, since it uses as much as digits as its factorization.

1011009999863 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 944784, while the sum is 56.

The spelling of 1011009999863 in words is "one trillion, eleven billion, nine million, nine hundred ninety-nine thousand, eight hundred sixty-three".