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1011009999917 is a prime number
BaseRepresentation
bin11101011011001001110…
…01000101010000101101
310120122121000200101000202
432231210321011100231
5113031022024444132
62052241313003245
7133020525131111
oct16554471052055
93518530611022
101011009999917
1135a848873885
12143b35253525
13744512b49a8
1436d0c79b741
151b47312d762
hexeb64e4542d

1011009999917 has 2 divisors, whose sum is σ = 1011009999918. Its totient is φ = 1011009999916.

The previous prime is 1011009999907. The next prime is 1011009999991. The reversal of 1011009999917 is 7199999001101.

1011009999917 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 651266754121 + 359743245796 = 807011^2 + 599786^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011009999917 - 210 = 1011009998893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011009999907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505504999958 + 505504999959.

It is an arithmetic number, because the mean of its divisors is an integer number (505504999959).

Almost surely, 21011009999917 is an apocalyptic number.

It is an amenable number.

1011009999917 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011009999917 is an equidigital number, since it uses as much as digits as its factorization.

1011009999917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 413343, while the sum is 56.

The spelling of 1011009999917 in words is "one trillion, eleven billion, nine million, nine hundred ninety-nine thousand, nine hundred seventeen".