101101000000493 has 2 divisors, whose sum is σ = 101101000000494. Its totient is φ = 101101000000492.

The previous prime is 101101000000459. The next prime is 101101000000579. The reversal of 101101000000493 is 394000000101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95775229936324 + 5325770064169 = 9786482^2 + 2307763^2 .

It is an emirp because it is prime and its reverse (394000000101101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101101000000493 - 2¹² = 101100999996397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101101000030493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550500000246 + 50550500000247.

It is an arithmetic number, because the mean of its divisors is an integer number (50550500000247).

Almost surely, 2^{101101000000493} is an apocalyptic number.

It is an amenable number.

101101000000493 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101000000493 is an equidigital number, since it uses as much as digits as its factorization.

101101000000493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 101101000000493 its reverse (394000000101101), we get a palindrome (495101000101594).

The spelling of 101101000000493 in words is "one hundred one trillion, one hundred one billion, four hundred ninety-three", and thus it is an aban number.