Base | Representation |
---|---|
bin | 1001001100011111000110… |
… | …0001000000101100000001 |
3 | 1022210111221221122022201002 |
4 | 2103013301201000230001 |
5 | 2311121001130310423 |
6 | 33300304224421345 |
7 | 2062300644111041 |
oct | 223076141005401 |
9 | 38714857568632 |
10 | 10110110010113 |
11 | 3248745592383 |
12 | 11734a7477855 |
13 | 5844c1392269 |
14 | 26d490b8b721 |
15 | 127ec1a1b228 |
hex | 931f1840b01 |
10110110010113 has 2 divisors, whose sum is σ = 10110110010114. Its totient is φ = 10110110010112.
The previous prime is 10110110010109. The next prime is 10110110010181. The reversal of 10110110010113 is 31101001101101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9805772427889 + 304337582224 = 3131417^2 + 551668^2 .
It is a cyclic number.
It is not a de Polignac number, because 10110110010113 - 22 = 10110110010109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10110110010094 and 10110110010103.
It is not a weakly prime, because it can be changed into another prime (10110110010613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055055005056 + 5055055005057.
It is an arithmetic number, because the mean of its divisors is an integer number (5055055005057).
Almost surely, 210110110010113 is an apocalyptic number.
It is an amenable number.
10110110010113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110110010113 is an equidigital number, since it uses as much as digits as its factorization.
10110110010113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 10110110010113 its reverse (31101001101101), we get a palindrome (41211111111214).
The spelling of 10110110010113 in words is "ten trillion, one hundred ten billion, one hundred ten million, ten thousand, one hundred thirteen".
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