Base | Representation |
---|---|
bin | 10110111111001101101111… |
… | …001101111101001011101101 |
3 | 111020222011121120022110222012 |
4 | 112333031233031331023231 |
5 | 101222420023341004442 |
6 | 555005112112531005 |
7 | 30203212351145102 |
oct | 2677155715751355 |
9 | 436864546273865 |
10 | 101101101109997 |
11 | 2a23981097042a |
12 | b40a0a2250a65 |
13 | 4454a400a01a1 |
14 | 1ad7468626aa9 |
15 | ba4d11c75582 |
hex | 5bf36f37d2ed |
101101101109997 has 2 divisors, whose sum is σ = 101101101109998. Its totient is φ = 101101101109996.
The previous prime is 101101101109993. The next prime is 101101101110033. The reversal of 101101101109997 is 799901101101101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67758398939401 + 33342702170596 = 8231549^2 + 5774314^2 .
It is a cyclic number.
It is not a de Polignac number, because 101101101109997 - 22 = 101101101109993 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101101101109991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550550554998 + 50550550554999.
It is an arithmetic number, because the mean of its divisors is an integer number (50550550554999).
Almost surely, 2101101101109997 is an apocalyptic number.
It is an amenable number.
101101101109997 is a deficient number, since it is larger than the sum of its proper divisors (1).
101101101109997 is an equidigital number, since it uses as much as digits as its factorization.
101101101109997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5103, while the sum is 41.
The spelling of 101101101109997 in words is "one hundred one trillion, one hundred one billion, one hundred one million, one hundred nine thousand, nine hundred ninety-seven".
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