Base | Representation |
---|---|
bin | 11101011011001001111… |
… | …00111100011000100011 |
3 | 10120122121002120210112011 |
4 | 32231210330330120203 |
5 | 113031022304342011 |
6 | 2052241350413351 |
7 | 133020536545141 |
oct | 16554474743043 |
9 | 3518532523464 |
10 | 1011011012131 |
11 | 35a8493a531a |
12 | 143b35661257 |
13 | 7445157a633 |
14 | 36d0c982591 |
15 | 1b47327d621 |
hex | eb64f3c623 |
1011011012131 has 2 divisors, whose sum is σ = 1011011012132. Its totient is φ = 1011011012130.
The previous prime is 1011011012101. The next prime is 1011011012147. The reversal of 1011011012131 is 1312101101101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011011012131 - 211 = 1011011010083 is a prime.
It is a super-2 number, since 2×10110110121312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1011011012101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505505506065 + 505505506066.
It is an arithmetic number, because the mean of its divisors is an integer number (505505506066).
Almost surely, 21011011012131 is an apocalyptic number.
1011011012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011011012131 is an equidigital number, since it uses as much as digits as its factorization.
1011011012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 1011011012131 its reverse (1312101101101), we get a palindrome (2323112113232).
The spelling of 1011011012131 in words is "one trillion, eleven billion, eleven million, twelve thousand, one hundred thirty-one".
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