101101112113 has 2 divisors, whose sum is σ = 101101112114. Its totient is φ = 101101112112.

The previous prime is 101101112053. The next prime is 101101112117. The reversal of 101101112113 is 311211101101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96576128289 + 4524983824 = 310767^2 + 67268^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101112113 - 2¹³ = 101101103921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101101112093 and 101101112102.

It is not a weakly prime, because it can be changed into another prime (101101112117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550556056 + 50550556057.

It is an arithmetic number, because the mean of its divisors is an integer number (50550556057).

Almost surely, 2^101101112113 is an apocalyptic number.

It is an amenable number.

101101112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101112113 is an equidigital number, since it uses as much as digits as its factorization.

101101112113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101101112113 its reverse (311211101101), we get a palindrome (412312213214).

The spelling of 101101112113 in words is "one hundred one billion, one hundred one million, one hundred twelve thousand, one hundred thirteen".