101101113011 has 2 divisors, whose sum is σ = 101101113012. Its totient is φ = 101101113010.

The previous prime is 101101112993. The next prime is 101101113031. The reversal of 101101113011 is 110311101101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101101113011 is a prime.

It is a super-2 number, since 2×101101113011² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101101112983 and 101101113001.

It is not a weakly prime, because it can be changed into another prime (101101113031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550556505 + 50550556506.

It is an arithmetic number, because the mean of its divisors is an integer number (50550556506).

Almost surely, 2^101101113011 is an apocalyptic number.

101101113011 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101113011 is an equidigital number, since it uses as much as digits as its factorization.

101101113011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 101101113011 its reverse (110311101101), we get a palindrome (211412214112).

The spelling of 101101113011 in words is "one hundred one billion, one hundred one million, one hundred thirteen thousand, eleven".