10110113301 has 4 divisors (see below), whose sum is σ = 13480151072. Its totient is φ = 6740075532.

The previous prime is 10110113291. The next prime is 10110113303. The reversal of 10110113301 is 10331101101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10110113301 - 2⁵ = 10110113269 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110113303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685018881 + ... + 1685018886.

It is an arithmetic number, because the mean of its divisors is an integer number (3370037768).

Almost surely, 2^10110113301 is an apocalyptic number.

It is an amenable number.

10110113301 is a deficient number, since it is larger than the sum of its proper divisors (3370037771).

10110113301 is an equidigital number, since it uses as much as digits as its factorization.

10110113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3370037770.

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 10110113301 its reverse (10331101101), we get a palindrome (20441214402).

The spelling of 10110113301 in words is "ten billion, one hundred ten million, one hundred thirteen thousand, three hundred one".