101101201001113 has 2 divisors, whose sum is σ = 101101201001114. Its totient is φ = 101101201001112.

The previous prime is 101101201001093. The next prime is 101101201001149. The reversal of 101101201001113 is 311100102101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63764249503504 + 37336951497609 = 7985252^2 + 6110397^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101201001113 - 2²¹ = 101101198903961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101101201001093 and 101101201001102.

It is not a weakly prime, because it can be changed into another prime (101101201091113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550600500556 + 50550600500557.

It is an arithmetic number, because the mean of its divisors is an integer number (50550600500557).

Almost surely, 2^{101101201001113} is an apocalyptic number.

It is an amenable number.

101101201001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101201001113 is an equidigital number, since it uses as much as digits as its factorization.

101101201001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101101201001113 its reverse (311100102101101), we get a palindrome (412201303102214).

The spelling of 101101201001113 in words is "one hundred one trillion, one hundred one billion, two hundred one million, one thousand, one hundred thirteen".