Base | Representation |
---|---|
bin | 11101011011001010001… |
… | …00100010000001101011 |
3 | 10120122121020022212011221 |
4 | 32231211010202001223 |
5 | 113031023312020243 |
6 | 2052241501202511 |
7 | 133020562501423 |
oct | 16554504420153 |
9 | 3518536285157 |
10 | 1011013001323 |
11 | 35a84a533886 |
12 | 143b36260437 |
13 | 74451ac5b80 |
14 | 36d0cd3d483 |
15 | 1b473522bed |
hex | eb6512206b |
1011013001323 has 32 divisors (see below), whose sum is σ = 1193221834560. Its totient is φ = 847603384320.
The previous prime is 1011013001293. The next prime is 1011013001377. The reversal of 1011013001323 is 3231003101101.
It is a cyclic number.
It is not a de Polignac number, because 1011013001323 - 25 = 1011013001291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011013001297 and 1011013001306.
It is not an unprimeable number, because it can be changed into a prime (1011013002323) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12180603 + ... + 12263323.
It is an arithmetic number, because the mean of its divisors is an integer number (37288182330).
Almost surely, 21011013001323 is an apocalyptic number.
1011013001323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1011013001323 is a deficient number, since it is larger than the sum of its proper divisors (182208833237).
1011013001323 is a wasteful number, since it uses less digits than its factorization.
1011013001323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84687.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1011013001323 its reverse (3231003101101), we get a palindrome (4242016102424).
The spelling of 1011013001323 in words is "one trillion, eleven billion, thirteen million, one thousand, three hundred twenty-three".
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