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1011021213011 is a prime number
BaseRepresentation
bin11101011011001011000…
…11110110110101010011
310120122121210210001111112
432231211203312311103
5113031032412304021
62052242353203535
7133021022342255
oct16554543666523
93518553701445
101011021213011
1135a8541323a7
12143b38b605ab
137445370c764
1436d10079cd5
151b4740e5d5b
hexeb658f6d53

1011021213011 has 2 divisors, whose sum is σ = 1011021213012. Its totient is φ = 1011021213010.

The previous prime is 1011021212987. The next prime is 1011021213043. The reversal of 1011021213011 is 1103121201101.

It is a weak prime.

It is an emirp because it is prime and its reverse (1103121201101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011021213011 - 234 = 993841343827 is a prime.

It is a super-2 number, since 2×10110212130112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011021216011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510606505 + 505510606506.

It is an arithmetic number, because the mean of its divisors is an integer number (505510606506).

Almost surely, 21011021213011 is an apocalyptic number.

1011021213011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011021213011 is an equidigital number, since it uses as much as digits as its factorization.

1011021213011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1011021213011 its reverse (1103121201101), we get a palindrome (2114142414112).

The spelling of 1011021213011 in words is "one trillion, eleven billion, twenty-one million, two hundred thirteen thousand, eleven".