Base | Representation |
---|---|
bin | 11101011011001011000… |
… | …11110111100100001011 |
3 | 10120122121210210012121122 |
4 | 32231211203313210023 |
5 | 113031032412403021 |
6 | 2052242353225455 |
7 | 133021022354102 |
oct | 16554543674413 |
9 | 3518553705548 |
10 | 1011021216011 |
11 | 35a854134684 |
12 | 143b38b6228b |
13 | 74453710c31 |
14 | 36d1007b039 |
15 | 1b4740e6bab |
hex | eb658f790b |
1011021216011 has 2 divisors, whose sum is σ = 1011021216012. Its totient is φ = 1011021216010.
The previous prime is 1011021216001. The next prime is 1011021216013. The reversal of 1011021216011 is 1106121201101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011021216011 is a prime.
It is a super-2 number, since 2×10110212160112 (a number of 25 digits) contains 22 as substring.
Together with 1011021216013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1011021216013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510608005 + 505510608006.
It is an arithmetic number, because the mean of its divisors is an integer number (505510608006).
Almost surely, 21011021216011 is an apocalyptic number.
1011021216011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011021216011 is an equidigital number, since it uses as much as digits as its factorization.
1011021216011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1011021216011 its reverse (1106121201101), we get a palindrome (2117142417112).
The spelling of 1011021216011 in words is "one trillion, eleven billion, twenty-one million, two hundred sixteen thousand, eleven".
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